Solution of the Diophantine Equation 143a + 665b = c2

  • Dinesh Thakur Department of Mathematics, Bahra University, Waknaghat, Solan, Himachal Pradesh, India.
  • Sunil Kumar Assistant Professor, Department of Mathematics, Dr. B.R. Ambedkar National Institute of Technology, Jalandhar, Punjab, India

Abstract

In this manuscript, authors studied the Diophantine equation 143𝑎 + 665𝑏 = 𝑐2, where 𝑎,𝑏,𝑐 are non-negative integers, and proved that (𝑎, 𝑏, 𝑐) = (1,0,12) is the unique non-negative integer solution of this Diophantine equation.

References

1. Thomas Koshy (2007) Elementary number theory with applications, 2nd edition, Academic Press, Amsterdam;
Boston.
2. Sroysang, B. (2014) On the Diophantine equation 7𝑥 + 31𝑦 = 𝑧2, International Journal of Pure and Applied
Mathematics, 92(1), 109-112.
3. Sroysang, B. (2014) More on the Diophantine equation 46𝑥 + 64𝑦 = 𝑧2, International Journal of Pure and
Applied Mathematics, 91(3), 399-402.
Published
2025-07-15
How to Cite
THAKUR, Dinesh; KUMAR, Sunil. Solution of the Diophantine Equation 143a + 665b = c2. Journal of Advanced Research in Applied Mathematics and Statistics, [S.l.], v. 10, p. 5-7, july 2025. ISSN 2455-7021. Available at: <http://www.thejournalshouse.com/index.php/Journal-Maths-Stats/article/view/1571>. Date accessed: 16 july 2025.